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11x+4.9x^2-19.5=0
a = 4.9; b = 11; c = -19.5;
Δ = b2-4ac
Δ = 112-4·4.9·(-19.5)
Δ = 503.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{503.2}}{2*4.9}=\frac{-11-\sqrt{503.2}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{503.2}}{2*4.9}=\frac{-11+\sqrt{503.2}}{9.8} $
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